Eisenstein’s Criterion
Example 118.1(∂).
Let be polynomials in , and irreducible polynomials, is irreducible in . Is an integral domain?
No, apparently. See Problem 2. If we set , , and , we have
so is a prime ideal. Note that is irreducible in . We can write , where is prime. This shows that cannot be prime.
Theorem 118.2(Eisenstein).
62ad0cLet be a UFD, and let be its field of fractions. Suppose
such that and .
If is an irreducible element in such that , for , , then is irreducible in . If is primitive, it follows (Theorem 115.10.6) that is irreducible in .
[!Proof]-
Let be as above. Write , where is primitive. It is sufficient to show that is irreducible in . The hypothesis given for continue to hold for (easy to show). Thus, we can assume WLOG that is primitive.
Suppose . Write and . Suppose . Then, or . If , then , since then . Suppose WLOG . Then, there exists an integer such that , and . Note that cannot be less than , since that would lead to a contradiction (see the expression for ).
[!Theorem]
Let be a Noetherian domain. a prime ideal. If is a ufd, then every prime ideal has height .