Suppose is a infinite field. Let be a vector space over . Show that cannot be written as a union of finitely many proper subspace. Does the same statement hold if is a finite field?

When F is an infinite field

FTSOC, Let , where are proper subspaces of . Pick a non-zero vector . Pick another non zero vector . Note that there are infinite vectors of the form , , and none of them are in . Thus, some , , must contain an infinite number of these vectors. must thus contain , and thus must contain . Since was arbitrary to begin with, we have shown that every can be found in , i.e, . We can proceed inductively to reach , which is impossible since is a proper subspace of . Thus, cannot be a finite union of proper subspaces.

When F is a finite field

A finite dimensional vector space over a finite field has a finite number of elements. Suppose the field    is finite, with  || = , where    is the number of elements in the field. Let    be a vector space over    with dimension  . This means that    has a basis consisting of    linearly independent vectors. Each element of    is a linear combination of the basis vectors. Specifically, if    is a basis for  , then every element of    can be written uniquely as:

where  .

Since    has    elements, each coefficient    in the linear combination has    possible values. Therefore, the total number of elements in    is .

Thus, it is easy to see that can be expressed as a finite union of proper subspaces.