Suppose is a infinite field. Let be a vector space over . Show that cannot be written as a union of finitely many proper subspace. Does the same statement hold if is a finite field?
When F is an infinite field
FTSOC, Let , where are proper subspaces of . Pick a non-zero vector . Pick another non zero vector . Note that there are infinite vectors of the form , , and none of them are in . Thus, some , , must contain an infinite number of these vectors. must thus contain , and thus must contain . Since was arbitrary to begin with, we have shown that every can be found in , i.e, . We can proceed inductively to reach , which is impossible since is a proper subspace of . Thus, cannot be a finite union of proper subspaces.
When F is a finite field
A finite dimensional vector space over a finite field has a finite number of elements. Suppose the field is finite, with || = , where is the number of elements in the field. Let be a vector space over with dimension . This means that has a basis consisting of linearly independent vectors. Each element of is a linear combination of the basis vectors. Specifically, if is a basis for , then every element of can be written uniquely as:
where .
Since has elements, each coefficient in the linear combination has possible values. Therefore, the total number of elements in is .
Thus, it is easy to see that can be expressed as a finite union of proper subspaces.